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Physics 13 Online
OpenStudy (anonymous):

a 5.5 D lens is placed 14cm from an object 4mm in height. what are the position, type height of the image? lens eq: 1/Do + 1/Di = 1/f

OpenStudy (anonymous):

Do = .14m Ho=.004m Di = ? f=?

OpenStudy (anonymous):

if f = -.18m how do I work this out in the lens eq?

OpenStudy (anonymous):

I have the correct answer, but I am missing something in the algebra i think because I can't get it.. Di = -.076m

OpenStudy (anonymous):

Sorry , what does D stands for (5.5 D ) ? and its unit ?

OpenStudy (anonymous):

thats the focal length

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

@mos1635

OpenStudy (mos1635):

sorry, no good in lences

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