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a 5.5 D lens is placed 14cm from an object 4mm in height. what are the position, type height of the image? lens eq: 1/Do + 1/Di = 1/f
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Do = .14m Ho=.004m Di = ? f=?
if f = -.18m how do I work this out in the lens eq?
I have the correct answer, but I am missing something in the algebra i think because I can't get it.. Di = -.076m
Sorry , what does D stands for (5.5 D ) ? and its unit ?
thats the focal length
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@mos1635
sorry, no good in lences
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