Question

What is the solution of the system? Use substitution.

x = –2y + 10
–6y = 6x – 6
z = –3x + 10y

A. x = 9, y = –8, z = 114

B. x = –8, y = 9, z = 114

C. x = –8, y = 114, z = 9

D. x = 114, y = 9, z = –8

Answer 1

b. x = –8, y = 9, z = 114

Answer 2

Can you use the first and second equality to find x and y?

Answer 3

you can do this by replacing x = -2y + 10 in second equation and solving for y
then plug this value of y in first equation to find x
then use these values of x and y in last equation to find z

Answer 4

x = –2y + 10
–6y = 6x – 6

x is -2y + 10
By using the substitution method
-6y = 6(-2y+10) -6
-6y = -12y+60-6
-6y = -12y + 54
-6y - -12y = 54
-6y + 12y = 54
6y = 54
y = 9

Then
if y = 9

x = –2y + 10
x = -2(9)+10
x = -18 + 10
x = -8

Now you have the value of x and y, can find the z?

Answer 5

@louis234 Please next time provide an explanation with your answer. It is against the Code of Conduct just to give the answer only.