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You roll 2 dice. What is the probability that the sum of the dice is prime and both dice show the number 6? Is it 1/36?
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12 is not a prime number
so this events are excludents
\[P(A \Omega B)=0\]
where A Sum is prime and B two faces six
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yeh Raphael is right.
If both dice need to show number 6, then the sum of the two dice is 12. 12 is NOT a prime number because it can be divisible by 2, 3, 4, 6, etc. Therefore, the probability is 0. :)
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