Question

Write the solution for the following problem as an ordered pair and two equations: The sides of a triangle have measures of x, x, and y, and the perimeter of the triangle is 46. The measure y is 4 centimeters longer than the measure x. Be sure to show all work.

Answer 1

The sides of a triangle have measures of x, x, and y, and the perimeter of the triangle is 46. The measure y is 4 centimeters longer than the measure x."

X + X + Y = 46 (can also be written as 2x + Y = 46)

Y + 2X = 46
Y - X = 4 *
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(Need to cancel the Y or the X, but cannot do so, so another step is needed)

* (Y - X = 4) / -1 (divide each number by -1) = -1Y + 1X = - 4

Y + 2X = 46
-Y + 1X = -4
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3X = 42 (divide both sides by 3)
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3 3
X = 14 (Now solve for Y)

y + (2 times 14) = 46
y + 28 = 46
1y = 46-28
1y = 18 (divide both sides by 1)
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1 1
Y= 18

So, 14 + 14 + 18 = 46
x + x + y = 46