Question

The length of a rectangle is 3 yd more than twice its width, and the area of the rectangle is 35 yd^2 Find the dimensions of the rectangle.

Answer 1

A = w * l
= w * ( 3 + 2w) = 35 yd²
Can you continue

Answer 2

lemme try

Answer 3

Post your solution, I'll be back to check it :)

Answer 4

this is what came up with me 3w+2w^2-35=0

Answer 5

Great, can you solve for w? ( just like x)

Answer 6

you want me to factor it ?

Answer 7

Yep!

Answer 8

ok i got it

Answer 9

-5,7/2

Answer 10

Wow, you're fast :D

Answer 11

where is the width and the length ?

Answer 12

Just take positive value width w = 3.5 ft
Can you plug it back to find length?

Answer 13

how did you get 3.5 ?

Answer 14

7/2

Answer 15

oh ok

Answer 16

so the equation its fonna be like this :
3.5=35.L

Answer 17

Check my first post to find out L = ...?

Answer 18

L=A/W

Answer 19

Nice try, but look more carefully :P

Answer 20

l=w/a ?

Answer 21

My first post, the second line! What do you understand?

Answer 22

You already had the width, now find out the relationship of width and length to => L

Answer 23

i cant get it

Answer 24

"The length of a rectangle is 3 yd more than twice its width"
=> L = 3 + 2w

Answer 25

so the length is 5 ?

Answer 26

What is your width?

Answer 27

3.5?

Answer 28

Length L = 3 + 2 * 3.5 = ....