Question

find three consecutive positive even integers such that the product of the second and third integers is twenty more than ten times the first integer

Answer 1

The integers are: x, x+2, x+4
\[(x+2)(x+4)=10x+20\]
\[x^2+6x+8=10x+20\]
\[x^2-4x-12=0\]
\[(x-6)(x+2)=0\]
\[x=6, x=-2\]
The integers are;
6,8,10 or -2,0,2

Answer 2

amazing. thnx:)