Question

any short way to solve this question. integrate (1+cos^2x)sin x dx

Answer 1

\[\int\limits_{}^{} (1+\cos ^{2}x) \sin x dx\]

Answer 2

Let u=cosx => du/-sinx
might work..

Answer 3

\[\int\limits(1+u^{2})sinx*\frac{du}{-sinx} \]

Answer 4

Can you do it from here?

Answer 5

yes get it