Question

plz help me d/dx(cot^-1)=?

Answer 1

y = 1 / ( cscx + cot x ) = csc x - cot x ....... (1)

dy/dx = d/dx( csc x ) - d/dx( cot x )

. . . . .= -csc x cot x - ( - csc² x )

. . . . .= csc x ( csc x - cot x ) ................... Ans.

OR . .= y· csc x .......... from (1) .............. Ans.
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Answer 2

the derivative of constant is zero.

Answer 3

so my ans.. is correct

Answer 4

not really,
http://www.math.com/tables/derivatives/tableof.htm

if it was cot^-1x|x=1, then answer would be -1/2