find the sum of ..... 1*1! + 2*2! + 3*3! + ....... + 50*50!
@Ishaan94 @apoorvk @Mani_Jha @experimentX help????
WBJEE?
\[T_n = n.n!\]
yup!!!! there are some sums which i have no idea of!!!
He's asking all those WBJEE questions which I couldn't solve :D
@Sarkar Me neither!
But 50! * 50! must be huge.
other ones i was able to solve(11 ones)!!!!,these i got stuck!!!
Magnanmous
\[\large(1!)^2 + (2!)^2 + \ldots + (50!)^2\]
\[\text{or you can write that as} \frac{(n+1)!}{n}\] Now what?
@Ishaan94 it's not n!*n!... read the question again.
guys i got a short trick but dont know if it is possible to apply here.!!!
Ohh yeah
\[\sum_{n=1}^{50}n.n!=\sum_{n=1}^{50}(n+1)!-n!\]you can use telescoping sum here and see all intermediate sums cancel out leaving just:\[51!-1!\]
this is using the fact that:\[(n+1)!=(n+1)*n!=n*n!+n!\]
its called cheating....LOL the series is given till 50! i did it for shorter series like till 1*1! + 2*2! =3! -1 1*1! + 2*2! + 3*3! =4! - 1 hence if the series is till 1*1! + 2*2! + 3*3! + ....... + 50*50! then as per my steps it should be 51! - 1
ohh asnaseer haz it. and sarkar too but how do i award medals now?
has*
give it to Sarkar - I don't mind :)
give it to the one who gave a better thoughtful,strategic ,accurate answer....
:) - well said Sarkar - just for that you deserve a medal! but honestly guys I really don't mind who gets medals - I'm on this site for the "joy" of learning and teaching - thats all.
well said@asnaseer and thanks for your explanation....
yw - I'm glad I was able to help
BTW: What is WBJEE?
i got another "nagging" Q coming your way in an hours time...
WEST BENGAL JOINT ENTRANCE EXAM
All Hail @asnaseer and @Sarkar !!
oh I see - thanks Sarkar and thanks apoorvk :D
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