Question

HELP please can someone help me with the steps for this problem...

Answer 1

what problem?

Answer 2

solving equations in quadratic form

Answer 3

2(x/x+1)^2-5(x/x+1)-3=0

Answer 4

- restriction that x not can being -1 because than the fractions are undefined
- sign x/(x+1) =y so than will get

2y^2 -5y -3=0
y_1,2=(5+/- sqrt(25+24))/4 =(5+/- sqrt49)/4 =(5+/- 7)/4 =
=-2/4 =-1/2 and 12/4 =3
- so now make

x/(x+1) = -1/2
2x = -x-1
3x=-1
x_1=-1/3

x/(x+1) =3
x=3(x+1)
x=3x+3
-3=2x
x_2=-3/2

- hope so much that you will understand it

good luck


bye

Answer 5

thanks i appreciated

Answer 6

yw

my pleasure