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Mathematics 8 Online
OpenStudy (anonymous):

Write in factored from. 2x^2+7x+3 8b^2+6b+1 8b^2-9b+1 6b^2+13b+2 12b^2-13b+3 3b^3+14b+8 5k^2+4k-1 2k^2-5k-3 3k^2+2k-5 7k^2-13k-2 10k^2-3k-1 6v^2-7v-3 5v^2+18v-8 4v^2-15v+9 3v^2+16v-12 8v^2-14v-15

OpenStudy (anonymous):

which one to factorize

OpenStudy (anonymous):

They all are.

OpenStudy (anonymous):

my god all of them

OpenStudy (anonymous):

Yup, mwhaha.

OpenStudy (anonymous):

okay i will solve one others will be solved in the same way ok

OpenStudy (anonymous):

Ok.

OpenStudy (anonymous):

2x^2+6x+x+3 2x(x+3)+1(x+3) (2x+1)(x+3)

OpenStudy (anonymous):

ok septicemic is it clear to u or not

OpenStudy (anonymous):

Not really...

OpenStudy (anonymous):

where are u finding difficulty ill explain u from there

OpenStudy (anonymous):

Is it 2x3=6 then only x can be taken out? Then 6/2=3? If so, I'm lost at +1(x+3)

OpenStudy (anonymous):

no its 6*1septicemic

OpenStudy (anonymous):

hence 6*1 will also add up to make seven that is with x

OpenStudy (anonymous):

6*1 is where?

OpenStudy (anonymous):

2 with x^2 will multiply with 3 of a constant which gives us answer 6.hence we will find out two numbers which will multiply to give six and will add up to make seven that is with x variable

OpenStudy (anonymous):

Ok.

OpenStudy (anonymous):

understood septicemic or did i made it more difficult with my explaining

OpenStudy (anonymous):

I got it.

OpenStudy (anonymous):

what about thanks donot i deserved or is it not allowed in your country to say thanks septicemic

OpenStudy (anonymous):

Thanks, I got the part you were explaining*

OpenStudy (anonymous):

u welcome i will be here if u feel any problem septicemic

OpenStudy (anonymous):

Ok.

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