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A 40 N force applied at an angle of 37 degrees above the horizontal pulls a 5-kg box on a horizontal floor. The acceleration of the box is 3m/s^2. How large a fritional force must be retarding the motion of the box?
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1. From the acceleration, work out the net horizontal force. 2. What is the value of the horizontal component of your 40-newton force ? 3. Work out the frictional force
DO you mean 40 - 3x 15
No, I don't. Use the 3 questions I provided in the right order. You can answer question 1, then draw a diagram and answer question 2. Will be here to help a few minutes more.
u mean 40cos 37 - 3x5
Yep ! ^_^
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