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find four consecutive odd integers such that the sum of the second and third is 19 greater than the fourth
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let numbers be n, n+2,n+4,n+6 then n+ 2 + n + 4 = n+ 6 + 19 solve this for n
thank you so much
yw
i know this is stupid but i just joined ... and i want to make sure... this is free right?
yes - absolutely
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im extremely happy now:)
lol
ohhh and one more thing... to make a new question... do i have to bump or remove my old one?
neither - just type in another question
so do i type close to get to an open box?
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oh - yes - sorry you have to do that
ok thanks... again:)
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