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HELP!!! Solve tan(x) (tan x +1)= 0 A. x= pi/3 ± 2pi n, x= 3pi/4 ± 2pi n B. x= ± pi n, x= 3pi/4 ± 2pi n C. x= ±pi n, x= pi/2 ± 2pi n D. x= ± n pi, x= pi/4 ± n pi
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tanx =0 means x= ± n (pi) tanx=-1 means x= 3pi/4 ± 2pi n Therefore option B is right
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