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If g(x) = |x-4| and h(x) = x^3; find (h 0 g)(-2) I have no idea what im doing...
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g(x) = |x-4| h(x) = x^3 h o g (x) = h(g(x)) = |x-4|^3 h(g(-2)) = |-2-4|^3 = |-6|^3 = 6^3 = 216
h(g(x)) means to take g(x) and put it into the input of h(x)
Thanksss
g()x=x-4 when x>=4 and g(x) = 4-x when x<4 to find hog(-2) u have to g(x)= 4-x since x=-2<4 h(g(x))=(4-x)^3 at x=-2 we have (4+2)^3=216
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