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Mathematics 8 Online
OpenStudy (anonymous):

question will be attached plz help if you can thank you!! :)

OpenStudy (anonymous):

OpenStudy (p0sitr0n):

Law of cosine : \[c^2=a^2+b^2 - 2abcos \theta\]

OpenStudy (p0sitr0n):

c =2, a =3, b=4

OpenStudy (anonymous):

2^2=3^2+4^2-2(3)(4)cos theta @P0sitr0n

OpenStudy (anonymous):

is it D?

OpenStudy (p0sitr0n):

\[\cos \theta =( c^2-a^2-b^2)/-2ab\]\[\cos \theta=\]0.875 answer B as it gives 21

OpenStudy (anonymous):

oh ok thank you!

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