Question

solve the equation by completing the square x^2-7x+1=0

Answer 1

\[x^2-7x+1=0\]
\[(x^2-7x+12.25)-12.25+1=0\]
\[(x-3.5)^2=11.25\]
x-3.5 = \[\pm \sqrt{11.25}\]
x =\[\pm \sqrt{11.25}\]+3.5