Question

factor n^2-19n+48

Answer 1

n^2-19n+48


n^2-16n-3n+48


(n^2-16n)+(-3n+48)


n(n-16)-3(n-16)


(n-3)(n-16)


This tells us that n^2-19n+48 completely factors to (n-3)(n-16)

Answer 2

thank you! (:

Answer 3

you're welcome

Answer 4

1. List factors of 48
List:
48, 1
24, 2
12, 4
6, 8
16, 3
48, -1
24, - 2
12, -4
6, -8
-3, 16
And so on...

2. Which of these factors adds up to -19?
Well the pair is -3 and -16

3. Since n is to the second power you'll get this as your answer...

(n - 3) (n - 16)

If I was not clear at some point, please do tell me and I'll elaborate.