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Mathematics 19 Online
OpenStudy (anonymous):

b^2+14b+45

OpenStudy (lgbasallote):

Hint: break down the middle term into factors of the last term

OpenStudy (lgbasallote):

that seems not clear...think of addends of 14 that when multiplied results to 45

OpenStudy (anonymous):

9*5

OpenStudy (anonymous):

b^2 + 14b + 45 = (b+9)(b+5) since: 9*5 = 45 and 9+5 = 14.

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