Question

solve
4(x-1)^2-9=27

Answer 1

i would suggest transposing the constant then getting the square root :D

Answer 2

what? haha

Answer 3

^there... see?

though @inthebleachers remember that the function is at degree 2..so you must have 2 values for x...missing one? /:)

Answer 4

4(x-1)^2 = 36
(x-1)^2 = 9 x-1 = [\sqrt{9}\]
x = +4 and -4

Answer 5

x - 1 = \(\sqrt 9\)
x - 1 = \(\pm 3\)

x - 1 = 3
x - 1 = -3

x - 1 = 3 +1
x - 1 = -3 + 1

so it's x = 4; x = -2

Answer 6

you got careless @inthebleachers :)