Question

solve
2(x+3)^2+10=8

Answer 1

\[2(x + 3)^2 + 10 = 8\]\[2(x + 3)^2 = -2\]\[(x + 3)^2 = -1\]\[(x + 3) = \pm \sqrt{-1} \]\[x = \pm \sqrt{-1} - 3\]

Answer 2

That has no solution in the real numbers, does it?

Answer 3

Yeah, thought so @exraven. I got the same answer.

Answer 4

well, the problem doesn't state \[x \in R\]so complex solutions are allowed