Determine whether the sequence is divergent or convergent. If it is convergent, evaluate it's limit. If it is divergent, is it positive or negative infinity.
A sub n= (13(3^n)+19)/(17(5^n))

Question

Determine whether the sequence is divergent or convergent. If it is convergent, evaluate it's limit. If it is divergent, is it positive or negative infinity.
A sub n= (13(3^n)+19)/(17(5^n))

anonymous · Answer

It appears to converge and the limit is 0. Think about it this way, for larger values of n, the constans won't matter, so we are left with:$$\lim_{n \rightarrow \infty} \frac{3^{n}}{5^n} = 0$$

lgg23 · Answer

Oh okay. So I can apply some of the basics of limits to sequences.