Question

Which function's graph has a period of 2?
A. y=cos( x-pi/2)
B. y= -4sin2x
c. y= 2 sinpix
D. y=3cosx

Answer 1

period of \(\sin(bx)\) is \(\frac{2\pi}{b}\)

Answer 2

set \(\frac{2\pi}{b}=2\) solve for \(b\)

Answer 3

you should get \(b=\pi\) so you are looking for \(\sin(\pi x)\)

Answer 4

so is C?

Answer 5

yes