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Which of the following is a polynomial with roots –2, –2i, and 2i? A. x^3 – 4x^2 + 4x – 16 B. x^3 + 4x^2 + 4x + 16 C. x^3 + 2x^2 + 4x + 8 D. x^3 – 2x^2 + 4x – 8
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your job is to multiply \[(x+2)(x+2i)(x-2i)\]
second part is easy, because \[(x+bi)(x-bi)=x^2+b^2\]
so your real job is to multiply \[(x+2)(x^2+4)\] and see what you get
wait, how do you multiply x and -2i?
x^3 + 4x + 2x^2 + 8 x^3 + 2x^2 + 4x + 8
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\[(x+2i)(x-2i)=x^2+2ix-2ix-2i\times 2i=x^2-4i^2=x^2+4\]
oh ok thanks!
yes you have it yw
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