Question

solve this equation using any method and explain the steps
3(w-2)^2-1=6

Answer 1

= (3w - 6)^2 - 1 = 6
= (3w - 6) ^ 2 = 7
= 3w^2 + 36 - 216w = 7
= (3w)^2 - 216w= -29
= 9w^2 - 216w = -29

Solve it further

Answer 2

3(w-2)^2=6+1
(w-2)^2=7/3

(w-2)=+(7/3)^(1/2) or, w=2+(7/3)^(1/2)
also
(w-2)=-(7/3)^(1/2) or, w=2-(7/3)^(1/2)
So there are two solutions

Answer 3

3(w-2)^2 -1 =6
(w -2)^2 =7/3
w-2=+/- sqrt(7/3)
w_1,2=2+/- (sqrt21)/3

Answer 4

- can you prove it for :

3((2+/- (sqrt21)/3 -2)^2 -1 =6
3((+/- (sqrt21)/3)^2 =7
3( 21/9)=7
21/3=7
7=7

Answer 5

ok ?