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how many six digit even numbers are possible if the left digit cannot be zero
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That's an interesting question. What's the only thing that matters when you're looking if a number is odd or even?
the last number
i think the answer is 450,000
exactly, because you have 9 possibilities for the first number, then 10 for the next 4 and 5 for the last, which gives you, as you found 9*10000*5
ok thanks for confiming
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