Question

The length of a rectangle is 5 more than twice its width, and the area of the rectangle is 88 ft^2 . Find the dimensions of the rectangle

Answer 1

16 l
5.5 w
i think

Answer 2

\[A=lw\]
\[l=2w+5\]
\[A=88\]
\[88=w(2w+5)\]
\[88=2w^2+5w\]
\[0=2w^2=5w-88\]
\[w=\frac{11}{2}\]

Answer 3

Let w = width then from the information given you can state;
l=2w+5 and we are given Area as 88 square feet. Area is length times width.
w(2w+5)= 88
\[2w ^{2}+5w=88\]\[2w ^{2}+5w-88=0\]
That will factor nicely (2w-11) (w+8)
w=11/2=5.5 ft.
l=16 ft.

check for correct area 16 X 5.5= 88 sq ft