Question

the equation sin(pi/6 -x) is equal to______?
a. 1/2 (sqrt3 cosx-sinx)
b. 1/2 (sqrt3 cos x+sin x)
c. 1/2 (cos x- sqrt3 sinx)
d. 1/2 (cosx+sqrt3 sinx)

Answer 1

\[\sin(a-b)=\sin(a)\cos(b)+\sin(b)\cos(a)\]
\[\sin(\frac{\pi}{6}-x)=\sin(\frac{\pi}{6})\cos(x)-\sin(x)\cos(\frac{\pi}{6})\]