Question

Three people were born in 1987. How many different ways can they celebrate their birthdays in 2009 if all three were born on different dates?

Answer 1

Hmn. Well the ways they can celebrate I think are practically independent of the dates of their birth. So for example, they could eat cake, have a sleep in, umm...

Answer 2

uh...any idea what the combination will look like?

Answer 3

1987 was not a leap year. So there were 365 days in the year. The first could have been born on any day. The second could have been born on every day except that (364 days). The third has 363 choices. For each choice of person one, next has 364 choices. For each choice of person two, person three has 363 choices. That's a multiplication type of arrangement. 365*364*363 different ways they can each have been born on a different day in 1987.

Answer 4

oh....:)!! you right! are you good with combinations and permutations?

Answer 5

Yes I am amazingly good. You just need to think about it a bit and then maybe one day you can be this good.

Answer 6

i'm going to be a fan :) can i ask you for future help please?

Answer 7

You can. I may or may not answer, depending on things.

Answer 8

actually do you mind helping me now if it doesnt take too much of your time?

Answer 9

like this question I just posted just mind boggles me...

Answer 10

would you agree that a) would be 10C8 ?

Answer 11

I'm not sure. I will sleep now. seeya.

Answer 12

ok. night night