Question

Factor: 64+27x^3

Answer 1

the plinomial is not factorable with real numbers.

Answer 2

I know I tried to solve it but it seems not factorable as you said

Answer 3

It's the sum of 2 cubes.
\[\begin{align}
64+27x^3&=4^3+(3x)^3\\
&=(4+3x)(4^2-4\cdot3x+(3x)^2)\\
&=(3x+4)(9x^2-12x+16)
\end{align}\]
For reference, the formula is:
\[a^3+b^3=(a+b)(a^2-ab+b^2)\]

Answer 4

(3x + 4)(9x^2
oh block has done it

Answer 5

Thank you guys

Answer 6

You're welcome. :D