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extremely hard problem, please help guys.. :S
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Here's my idea: When the water rises to the corner then the water will form a frustum of a pyramid. The volume of this frustum is (h/3)(B1+B2+sqrt(B1B2)) where B1 and B2 are the areas of the bases. B1, the bottom base, is 1.
Exactly what @blockcolder said.
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