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OpenStudy (anonymous):
Simplify (x + 4)(x2– 6x + 3)
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OpenStudy (blockcolder):
Use distributive property: \[(x+2)(x^2-6x+3)=x(x^2-6x+3)+2(x^2-6x+3)\]
OpenStudy (anonymous):
a.x3– 14x2+ 3x + 12 b.x3– 6x2– 17x + 12 c.x3– 10x2– 27x + 12 d.x3– 2x2– 21x + 12 would it be c?
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