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Simplify x-2/x^3-8
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(x^4-8 x^3-2)/x^3
Hint: Factor the denominator.
can you show me how to factor denom
You will soon recognize certain binomials. the X^3 - 8 is one. It is known as the difference of two perfect cubes. Note that the x is cubed and the 2 is cubed. The configuration has factors that you may eventually memorize. They are (x-2)(x^2+2x+4)
The general equation is: \[x ^{3}-a ^{3}=(x-a)(x ^{2}+ax+a ^{2)}\]
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In this problem the a^3 is the 2^3 (8)
(x-2)(x^2+2x+4)
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Yea
Now to solve your problem it was (I will draw)|dw:1335228277956:dw|
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