Question

Solve the Inequalities:
-k/3 + 8 < 7

Answer 1

This is the real one:
\[-k/3+8\le7\]

Answer 2

\[ -\frac{k}{3}+8\le7\]\[ -\frac{k}{3}+8-8\le7-8\]\[ -\frac{k}{3}\le-1\]\[ -\frac{k}{3} \times(-3)\ge-1\times(-3)\]\[ k\ge3\]

Answer 3

what does that mean?

Answer 4

What do you mean? You can't see the latex?

Answer 5

Or you don't understand ?

Answer 6

the first one....i think

Answer 7

(-k/3) + 8 ≦7
(-k/3) + 8 -8≦ 7-8
(-k/3) ≦ -1
(-k/3) x (-3) ≧ -1 x (-3)
k ≧ 3
Got it?

Answer 8

kind of

Answer 9

Hmm.. Which part you don't understand?

Answer 10

i think i got it im just looking at it harder

Answer 11

i get it up to step 5

Answer 12

lol Step 5 is the last step...

Answer 13

i ment 4 sorry

Answer 14

You don't understand the change of sign?

Answer 15

nevermind i got it, thanks so much!!

Answer 16

Glad to know that you understand. You're welcome. Ask if you have any questions :)

Answer 17

well do