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OpenStudy (anonymous):
(3/x) + (2/x+2) / (3/x+2) - (2/x)
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OpenStudy (anonymous):
Please help me and Thank you
sam (.sam.):
((3)/(x))+(x+2)/(3)*(2)/(x+2)+((2)/(x)) (3)/(x)+(2)/(3)+(2)/(x) (5)/(x)+(2)/(3) (2x+15)/3x
OpenStudy (blockcolder):
Can you write the function for us?
OpenStudy (anonymous):
Thank you .Sam.
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