Question

is it correct that for the function f(x)=√((x-3)^2 +3)
the domain= { 0≤x , ∞} and
range= {√3 ≤ y, ∞} ?

Answer 1

no domain is all real numbers since \((x-3)^2\geq 0\) always and so \((x-3)^2+3\geq 3\)

Answer 2

you do have the range correctly

Answer 3

okay thanks!