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Solve 3x-6y+5z=2 when x=2 and z = -2
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Plug 2 in where x is and -2 for z and solve for y
So substitute the values of x and z and solve for the remaining y..
3(2)-6y+5(-2)=2
The reason I ask this is because in the system 3x-6y+5z=2 3x+3y-z=5 5x+6y+5z=-6 When I try to plug in the values and solve for y, I get a strange answer... but when I plug it into the other equations, I get the correct answer. Why is this?
I don't understand -6y = 8??
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WAIT
Is it possible for it to be a fraction?
NO FREAKING DUH... I SWEAR I'M HALF ASLEEP RIGHT NOW
Oh ill wait:)
4+2 = 6. lol
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lol, There you go!
Im half asleep too!!
lol :)
Glad I could help...sorta! lol:)
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