The length of a rectangle is twice its width.
If the perimeter of the rectangle is 54yd , find its area.

Question

The length of a rectangle is twice its width. 
If the perimeter of the rectangle is 54yd , find its area.

callisto · Answer

Let l be the length.
length of a rectangle is twice its width => width = length /2 = l/2
Perimeter = 2 (length + width) = 2 (l + l/2) = 54
                                                           3l    = 54
                                                              l   = 18
Area = length x width = l (1/2) = 18 ( 18/2) = 162

anonymous · Answer

cool thats what I got, your awesome man(: