Question

How would you integrate this?
\[\int (tanu+cotu)^2 du\]

Answer 1

Well, expand it..

Answer 2

My attempt:
\[\int (tanu+cotu)^2=\int (tan^2u+2+cot^2u) du\]\[=\int (sec^2u-1+2+csc^2u-1)= \int sec^2u +csc^2u du \]\[= tanu - cotu +C\]
Any better method?

Answer 3

For the third step... I forgot to put du at the end:(

Answer 4

lol, i did the same..was about to type that. xD

Answer 5

Oh...Thanks!!!!~

Answer 6

Sorry I didnt help much..but im sure there's another method..

Answer 7

Nope!~ You did help!!! I always forget how to do this question :S