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Mathematics 11 Online
OpenStudy (anonymous):

Absolute value : |2x-1| < 4x-2 I don't know which is the answer

OpenStudy (aravindg):

u hav to see 2 conditions here

OpenStudy (aravindg):

either x>0 or x<0

OpenStudy (aravindg):

when x>0 then 2x-1<4x-2 1<2x x>1/2

OpenStudy (saifoo.khan):

|2x-1| < 4x-2 2x - 1 < 4x - 2 2x - 1 > -(4x-2)

OpenStudy (aravindg):

similarly do for x <0

OpenStudy (anonymous):

@saifoo.khan yes, im already there, so lastly, there will be 2 answers right? how do u determine which answer is correct?

OpenStudy (saifoo.khan):

Both will be correct.

OpenStudy (aravindg):

ys both are correct

OpenStudy (anonymous):

so that means there will be two answers? doesn't it has to agree with the "<" sign?

OpenStudy (aravindg):

2 answers

OpenStudy (saifoo.khan):

the inequalities can be same and different. that dosn't really matter.

OpenStudy (anonymous):

okay thank you again :)

OpenStudy (saifoo.khan):

Welcome

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