Question

volume of a solid whose base is 1/9 *x^2 + y^2=1 and having a square cross section perpendicular to the x axis

Answer 1

volume. of a solid. not area of a cross section

Answer 2

find the area ... y = sqrt(1 - 1/9 x^2)

area = 4 * integrate from 0 to 3 sqrt(1 - 1/9) dx

volume = area * height

Answer 3

why is it from 0 to 3
also why is it 4 times the integral? shouldn't it be the function inside the integral squared?