Question

find the quadratic polynomial that has a minimum value of -3 when x=-2 and passes through the point (1,6)

Answer 1

vertex(-2,-3)
y=a(x+2)^2-3
put (1,6)
6=a(1+2)^2 -3
9=9a
a=1
therefore, the required equation is y=(x+2)^2-3

Answer 2

thank you! =]