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Find the solution to the system of equations. 2x + 4y + 2z = -8 5y - 2z = 0 4z = -20 A. x = 4, y = -1, z = -5 B. x = -3, y = 2, z = 4 C. x = 5, y = 0, z = 2 D. x = 5, y = -2, z = -5
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z= -5 That leaves options a and d D is the answer. Try substituting all values.
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