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Given: ABCD is a trapezoid. ΔAYD is congruent to ΔBCY. ABYD is a rhombus. AD=3 and AX=1. Find the length of all sides and diagonals
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By Pyth. Thm. \[DX =\sqrt{3^2-1^2} = \sqrt{8}\] \[DX = XB = \sqrt{8}\] \[DB = DX+XB = 2\sqrt8 =4\sqrt2 \] XY = AX = 1 AY = XY + AX =2 YD = BA = 3 Since ΔAYD is congruent to ΔBCY CY=YD = BA = 3 DC = CY +YD = 3+3 =6 BC = AY = 2 Done!
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yes i had my online teacher like th ne who supervises the class look over it and explain. i didnt know he was good at math.
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