Question

Can anyone help me find this derivative?

Answer 1

yess (:

Answer 2

\[\ln (e ^{x ^{3} } + x ^{3})\]

Answer 3

Chain rule

Answer 4

\[\LARGE \ln (u)'=\frac{1}{u}\cdot (u)'\]

Answer 5

What kresnik said.

Answer 6

dlnu=1/u

de^(u^a) =(au^(a-1))e^(au) where a is a constant
d ln(e^(x^3)+x^3)
=(1/((e^(x^3)+x^3))((3x^2)(e^(x^3)+3x^2)