Question

would this be right..
Ix-12I=3

15,-9 ??

Answer 1

|x-12|=3
now we have two cases:
x-12=3 or x-12=-3
solving them we get:
x=3+12 x=-3+12
x=15 x=9

Answer 2

could you help me with this one

Answer 3

is it 5, -7/3

Answer 4

|x+6|=2x+1

x+6=2x+1 x+6=-(2x+1)
x-2x=1-6 x+6=-2x-1
-x=-5 x+2x=-1-6
x=5 3x=-7
x=-7/3

Yes your result is correct. Well done :)

Answer 5

sweet, thank you!

Answer 6

My pleasure xD