Question

Find an equation of the tangent to the curve at the point corresponding to the given value of the parameter . . .

Answer 1

\[x = t^4 +1\]
\[y = t^3 + t\]
\[t = -1\]

Answer 2

Can you solve this if you're given a function y(x)?

Remember that y'(x)=dy/dx=(dy/dt)/(dx/dt)

Answer 3

I can find the slope of the tangent, but what do I do with that information?

Answer 4

OH WAIT.

y - y0 = m(x - x0), right?

Answer 5

yeah. Can you get y0 and x0?

Answer 6

Yes! I just plug in t = -1?

Answer 7

Awesome, thanks :)

Answer 8

cool. What did you get?