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Mathematics 23 Online
OpenStudy (anonymous):

i)Find the max/min value of y ii) Where this occurs for y=-1/2(x-1)^2

OpenStudy (anonymous):

max is zero because you have a square , which is never negative, and then a minus sign out front, so it is never positive. biggest it can be is zero

OpenStudy (anonymous):

you can tell what value of x makes it zero pretty much by your eyeballs.

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