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Again plz, definite integrals?
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\[\int\limits_{2}^{3}\left( 1/\left( xlnx \right) \right)dx\]
let lnx = u, du = 1/x dx
Did you try u=ln(x) ? :)
i cant get it
\[\int\limits_{}^{}\frac{1}{\ln(x)} \cdot \frac{1}{x} dx\]
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\[\int\limits_{}^{}\frac{1}{u} du\]
so its ln(lnx) +K this is the next step right?
\[ \ln \left| \ln\left| 3 \right| \right|- \ln \left| \ln\left| 2 \right| \right|\]
thank you all so much
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