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OpenStudy (anonymous):
The absolute (global) maximum and absolute minimum function values of f(x)=x^3-3x^2+1 on the interval [(-1/2),4]
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OpenStudy (anonymous):
1º find the derivative. 2º make it equal to 0 and find which value from the interval makes it 0. 3º check the values that you got in 2º and alo the endpoints of the interval -1/2 and 4 pluging them into orifinal equation
OpenStudy (anonymous):
Is the answer 2,0?
OpenStudy (anonymous):
or 1, -3?
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